ABC is a triangle in which AB = 3 cm, BC = 4 cm and ∠B = 90°. The circle with diameter AB intersects AC at D and tangent to the circle at D intersects BC at E. Then EC is equal to

AOB is the diameter of the circle (centre O) and C is a point on the circle such that AC = BC. Then ∠CAB is:

If ABC is an isosceles triangle with AB = AC. E and F are points on BC and AC respectively such that AE = AF. If ∠BAE = 40°, then ∠FEC is equal to

The sides of a triangle are 5, 12 and 13 units. A rectangle is constructed, which is equal in area to the triangle. It has a width of 10 units, then the perimeter of this rectangle is :

ABC is a triangle with sides AB = 41 cm, BC = 28 cm and CA = 15 cm. If D, E and F are the mid-points of AB, BC and CA respectively, then what is the area of the triangle DEF?

The sides of an equilateral triangle are (2a – b) cm, (a + 3b) cm and (2a – 2b + 1) cm then the perimeter of the triangle is