The position vector of a particle is r⃗ = 2t² x̂ + 3t ŷ + 4 ẑ. Then the instantaneous velocity v⃗ and acceleration a⃗ respectively lie

A car has an initial velocity of 12 m/s and is brought to rest over a distance of 45 m. The acceleration of the car is

A particle is moving in a uniform circular motion with constant speed V along a circle of radius r. The acceleration of the particle is

The area under the velocity-time graph for a particle moving in a straight line with uniform acceleration gives

Statement: An object of mass M is falling freely and its acceleration remains constant. Conclusion I: The velocity of the object increases uniformly. Conclusion II: The acceleration of the object dep…

What is the nature of velocity-time graph for a car moving with uniform acceleration?