There are four persons A, B, C, D; and A has some coins. A gave half of the coins to B and 4 more besides. B gave half of the coins to C and 4 more besides. C gave half of the coins to D and 4 more besides. Both B and D end up with same number of coins. How many coins did A have originally?
Related questions
A man fills a basket with eggs in such a way that the number of eggs added on each successive day is the same as the number already present in the basket. This way the basket gets completely filled i…
SimplificationFather is aged 3 times more than his son after 8 years, he would be two and half times of his son's age. after further 7 years, how many times would he be of his son's age?
Simplification5 equivalent vertical lines are drawn on a board. 5 equidistant horizontal lines are also drawn on the board cutting the 5 vertical lines and the distance between any two consecutive horizontal lines…
SimplificationA number is first decreased by one-fifth of its value and then increased by one-fourth of the resulting value. If the final result is 48, what was the original number?
SimplificationA gardener plants 1000 trees in a square grid with equal rows and columns. How many trees remain after forming the largest possible square?
Simplification